model 3 based on positive and negative exponent Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC FCI Ass Grade-III 2013]

If a = 7 - $4√3$, the value of $a^{1/2}+ a^{-1/2}$ is

a) 4

b) $2√3$

c) 7

d) $3√3$

Answer:(a)

a = 7 - $4√3$

$1/a=1/{7-4√3}$

=$1/{7-4√3}×{7+4√3}/{7+4√3}=7+4√3$

$(√a+1/√a)^2=a+1/a+2$

$=7-4√3+7+4√3+2=16$

$√a+1/√a=4$

Question : 2

$4^61 + 4^62 + 4^63 + 4^64$ is divisible by

a) 3

b) 13

c) 11

d) 17

Answer:(d)

$4^61 + 4^62 + 4^63 + 4^64$

= $4^61 (1 + 4 + 4^2 + 4^3)$

= $4^61(1 + 4 + 16 + 64)$

= $4^61$ × 85 which is divisible by 17.

Question : 3

If $x = 3^{1/3} - 3^{-1/3}$, then $(3x^3 + 9x)$ is equal to

a) 6

b) 8

c) 7

d) 5

Answer:(b)

$x = 3^{1/3}- 3^{-1/3}$

On cubing both sides,

$x^3 = ((3)^{1/3})^3 -((3)^{-1/3})^3 -3×3^{1/3}×3^{-1/3}(3^{1/3}- 3^{-1/3})$

$x^3 = 3 - 3^{ - 1}$ - 3x

$x^3 + 3x = 3 - 1/3$

$x^3 + 3x = {9 -1}/3 = 8/3$

$3x^3$ + 9x = 8

Question : 4 [SSC CGL Tier-I 2016]

If $2^{x + 4} - 2^{x + 2}$ = 3, then the value of 'x' is :

a) 2

b) - 2

c) - 1

d) 0

Answer:(b)

$2^{x+4} - 2^{x+2}$ = 3

$2^{x+2}(2^2 - 1)$ = 3

$2^{x+2}$× 3 = 3

$2^{x+2}$ = 1 = 2°

x + 2 = 0 ⇒ x = - 2

Question : 5 [SSC CGL Tier-I 2014]

Arranging the following in ascending order $3^34, 2^51, 7^17$ we get

a) $7^17 > 2^51 > 3^34$

b) $2^51 > 3^34 > 7^17$

c) $3^34 > 7^17 > 2^51$

d) $3^34 > 2^51 > 7^17$

Answer:(d)

$3^34 = (3^2)^17 = 9^17$

$2^51 = (2^3)^17 = 8^17$

$7^17 = 7^17$

Clearly, $9^17 > 8^17 > 7^17$

i.e., $3^34 > 2^51 > 7^17$

IMPORTANT quantitative aptitude EXERCISES

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